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carried out entirely at compile-time: there's no operate-time House or velocity Expense for your const. From the pass by benefit
However In case the caller provides a const MyFredList a or const MyFredList& a, then a[three] will get in touch with the const subscript
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To paraphrase, “X& const x” is functionally such as “X& x”. Because you’re attaining absolutely nothing by introducing the
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need to simply call either g() operate, an area duplicate with the std::string object has to be passed for the g() function; the
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